First divide both sides by 5! Then notice that the equation
only involves two terms! Also notice that the value left on the
right hand side of the equation is a perfect square number!
5x = 500 Given equation
x = 100 Divide by 5
Thus x = ± 10 meaning x can be +10 or x can be -10!
b: Solve x = 7
Notice that the equation only involves two terms! Also notice
that the value left on the right hand side of the equation is NOT
a perfect square number! So what !!! You can still solve this by
extracting square roots.
x = 7
So x = ± 7
c: Solve (x- 2) = 64
METHOD 1: Notice that the left hand side of
the equation is still a squared term. It just happens to be x -2!
It can be solved by taking the square root of both sides as
follows:
(x- 2)= 64
So x - 2 = ±8
Thus x - 2 = 8 or x - 2 = -8
x = 10 or x = -6
METHOD 2: Clear the parentheses, collect like
terms on left, set = 0, factor!
(x- 2) = 64
x -4x + 4 = 64
x -4x + 4 - 64 = 0
x -4x - 60 = 0
(x - 10)(x + 6) = 0
Either x - 10 = 0 or x + 6 = 0
x = 10 or x = -6
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= 500 
